Sokka was true to his word.

Zuko conveniently decided, the morning after Yue spoke with her former boyfriend, that it was a great time for a reunion/celebration-of-victory party (even though it had only been a few weeks since they went their separate ways, and his coronation had kind of been a victory celebration).

It was a nice party – small, just family and the friends they had made during their travels. Every vital person was present, making the role of matchmaker that much easier.

Well, in theory.

In actuality, it proved rather difficult to split the two couples apart, let alone get the right ones together. It wasn't until two hours into the party and many failed attempts that Sokka finally had success.

First he, Katara, Aang, and Suki went out to the gardens to admire the scenery and chat. Then, after a strategically inconspicuous amount of time, he led Aang back into the party by simply walking in that direction while telling a deeply intriguing story (Suki was in on the plan (though not to midnight-visit details) and knew to keep Katara fully occupied). Later, he shoved Aang off to a random party guest and moved on to Zuko and Mai, leading them out to the gardens the same way he had with the first group. Another calculated period of time sent Suki and Mai off, discussing weapons (which still amazed Sokka – wasn't 'girl talk' supposed to be about make-up and that thing that happened every month?), and another few minutes had Sokka disappearing to 'find his girlfriend'.

And, finally, the potential lovebirds were alone.

The whole strategy was apparently based on a riddle he had learned from someone during their travels. Though, the original involved people trying to cross a river on a boat, not a love-square which all involved members were oblivious to.

But it was a step in the right direction and it made Yue's job that much easier.


Author's Notes: You guys probably know the riddle I'm referring too, right? I'm still not sure I know how to solve it. xD

Disclaimer: I do not own 'Avatar' or any of its characters.